| Ruud H.G. van Tol on Tue, 24 Mar 2026 11:53:41 +0100 |
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| add listsum( L, {n=#L}, {s=1} ) |
Consider adding listsum( L, {i1 = 1}, {i2 = #L} ).
Much like vecsum( Vec( L[ i1 .. i2 ] ) ) would be,
but without copying any data.
-- Ruud