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Bill Allombert on Fri, 18 May 2012 18:23:14 +0200
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- To: pari-users@pari.math.u-bordeaux.fr
- Subject: Re: zetap
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux1.fr>
- Date: Fri, 18 May 2012 18:23:07 +0200
- References: <CAKDc=ZxJChWKrkmuyL92o8UWaM_Ac8zFF8otn5ZFvGtTCUpm-A@mail.gmail.com> <20120512162459.GA4507@math.u-bordeaux1.fr> <CAKDc=Zw00vfRvqHfvyHRs427u6G5T6uRmvMt9UqYs1Le8xPgvw@mail.gmail.com> <20120514141254.GA25306@yellowpig> <CAKDc=Zx0rBBQ112dyc3UyXs63KMTW7qZFDwnmwDOtLWCDs7L-A@mail.gmail.com> <20120515194446.GI4506@yellowpig> <CAKDc=ZxKQr0Dp-KgumPnVn5Ok5pXWvnrWGdnx1QF5aK5ZmoZLg@mail.gmail.com> <CAKDc=Zz1ZwmeppbA9xE3r6Xwokh=+Gb0P8d4eUE4ZfV795h6Fg@mail.gmail.com> <CAKDc=ZxuLD8=JDxUQkR4Ge8zj0pLxB1gXOxRm9a03pfcd+Xy5A@mail.gmail.com>
On Fri, May 18, 2012 at 06:04:53PM +0200, sou nonyma wrote:
> i found that i was not clear so here are few value of my algorithme:
> in the formula:
> zetap(4)=3+2*3^2+2*3^6+2*3^7+O(3^8) (i have change a few things since
> i put the previous message)
> <x>=<1/p>=1+O(3^8)
> the conbination C(1-s,1) for exemple C(-3,1)=
> 2+2*3+2*3^2+2*3^3+2*3^4+2*3^5+2*3^6+2*3^7+O(3^8)
> the bernoulli number 6 B(6)=2*3^-1+3^2+2*3^3+2*3^4+3^5+O(3^6)
> and the term for k=1 which is =2*3^3+3^4+3^5+3^6+3^7+O(3^8)
Well, since zeta(-5) is -1/252, by definition of the p-adic zeta function, we must have
zeta(4+O(3^2)) = zeta(-5+O(3^2)) = -1/252+O(3^-1) = 2*3^-2+O(3^-1)
which is what PARI gives.
Look at your formula to see why you do not get the right valuation.
Cheers,
Bill.
- References:
- zetap
- From: sou nonyma <sounonyma@gmail.com>
- Re: zetap
- From: Karim Belabas <Karim.Belabas@math.u-bordeaux1.fr>
- Re: zetap
- From: sou nonyma <sounonyma@gmail.com>
- Re: zetap
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux1.fr>
- Re: zetap
- From: sou nonyma <sounonyma@gmail.com>
- Re: zetap
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux1.fr>
- Re: zetap
- From: sou nonyma <sounonyma@gmail.com>
- Re: zetap
- From: sou nonyma <sounonyma@gmail.com>
- Re: zetap
- From: sou nonyma <sounonyma@gmail.com>