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Bill Allombert on Tue, 20 May 2025 21:29:49 +0200
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Re: forpart of zero and fixed length
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- To: pari-users@pari.math.u-bordeaux.fr
- Subject: Re: forpart of zero and fixed length
- From: Bill Allombert <Bill.Allombert@math.u-bordeaux.fr>
- Date: Tue, 20 May 2025 21:29:45 +0200
- Delivery-date: Tue, 20 May 2025 21:29:49 +0200
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On Tue, May 20, 2025 at 02:52:20PM -0400, Max Alekseyev wrote:
> On a related note, I do not understand why I'm getting different results in
> the following two examples (fist one looks like a bug):
>
> ? forpart(p=5,print(p),[0,5],[2,2])
> Vecsmall([1, 4])
> Vecsmall([2, 3])
This is correct: the length is the number of nonzero entries.
> ? forpart(p=5,print(p),[0,5],2)
> Vecsmall([0, 5])
> Vecsmall([1, 4])
> Vecsmall([2, 3])
>
> Also, in the second case, shouldn't 2 be interpreted as nmax and partitions
> with smaller parts (=1) be also generated?
By default, parts are positive and we remove zero entries unless amin <= 0, in which case we fix the size #X = nmax.
Cheers,
Bill.