reduction in time for qfbsolve() is about 2/3 hr for c=216521

American Citizen on Sun, 05 Apr 2026 22:48:24 +0200

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reduction in time for qfbsolve() is about 2/3 hr for c=216521

To: pari-users <pari-users@pari.math.u-bordeaux.fr>
Subject: reduction in time for qfbsolve() is about 2/3 hr for c=216521
From: American Citizen <website.reader3@gmail.com>
Date: Sun, 5 Apr 2026 13:48:19 -0700

One last comment on qfbsolve() time savings using [N,F]

For where I am currently running with c = 216521

running b from c to 10*c  took:

old:  11545424 ms

new: 9188600 ms

less:  2356724 ms or almost 2/3 of an hour.

This for around 3 hours for the run so I am happy about saving 2356.824seconds


Randall

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